Quote:
Originally posted by Pussy_Kat
^^^^ mmmm k
so the oxygen cuz its the limiting reactant get x/5 and C3H8 gets x/its moles right?
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your getting there, but that's not quite the way to think about it.
Whether or not O2 is the limiting reagent, you would still use the coefficient - we are using C3H8's coefficient in the equation as well, it just happens to be 1 so you don't notice it. We would use ALL the coefficients of ALL the molecules when figuring these problems out, because they are the RATIOs of one type of molecule to the others - in this case it's a 5 to 1 ratio. Like I said above,
the reason the coefficients are there are to balance the equation - which like i said above means that we will need 5 oxygen molecules (O2's) for every propane molecule (C3H8).
I'm not sure how else I can explain this.